how can i re-write the equation:
t = -100 ln(9.8 - 0.01v)
to make v the subject?
i think it has something to do with e^t or something like that
but i really need help
thanks
$\displaystyle t = -100 \ln(9.8 - 0.01v) $
$\displaystyle \frac{t}{-100} = \ln(9.8 - 0.01v)$
then EXP both sides XD
$\displaystyle exp(\frac{t}{-100} ) = exp(\ln(9.8 - 0.01v))$
$\displaystyle exp(\frac{-t}{100} ) = 9.8 - 0.01v $
$\displaystyle 9.8 - exp(\frac{-t}{100} ) = 0.01v $