Given the curve F(x)=x^2-3x+7. If A is the point where x=3 and B is the point where x=5, find the equation of the secant AB.
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Originally Posted by deej813 Given the curve F(x)=x^2-3x+7. If A is the point where x=3 and B is the point where x=5, find the equation of the secant AB. Can you find the equation of a line that passes through the points (3,7) and (5,17)?
yeah i got the gradient as 5 then the equation using the y-y1=m(x-x1) as 5x-y-8=0 but the answer says 7x-2y-1=0 what did i do wrong??
Originally Posted by deej813 yeah i got the gradient as 5 then the equation using the y-y1=m(x-x1) as 5x-y-8=0 but the answer says 7x-2y-1=0 what did i do wrong?? The work is right, but either the function you posted is incorrect, or one (or both) of the A and B values are incorrect.
ok well they are all right so maybe the answer is just wrong thanks heaps
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