Simplify and multiply this equation

**fcabanski** · August 26th 2009, 09:57 AM

I can solve this through substitution since it's multiple choice ( $X/(X-1)$ , but how is it simplified?

(( $9x^2-4$ ) $/$ ( $3x^2-5x+2$ )) * ( $(9x^4-6x^3+4x^2$ )/ $27x^4+8x$ )

**masters** · August 26th 2009, 10:36 AM

Originally Posted by fcabanski

I can solve this through substitution since it's multiple choice ( $X/(X-1)$ , but how is it simplified?

(( $9x^2-4$ ) $/$ ( $3x^2-5x+2$ )) * ( $(9x^4-6x^3+4x^2$ )/ $27x^4+8x$ )

Hi fcabanski,

$\frac{9x^2-4}{3x^2-5x+2}\cdot \frac{9x^4-6x^3+4x^2}{27x^4+8x}$

Let's factor the thing.

$\frac{(3x-2)(3x+2)}{(3x-2)(x-1)}\cdot \frac{x^2(9x^2-6x+4)}{x(27x^3+8)}$

$\frac{(3x-2)(3x+2)}{(3x-2)(x-1)}\cdot \frac{x^2(9x^2-6x+4)}{x(3x+2)(9x^2-6x+4)}$

How's this for a start?

**fcabanski** · August 26th 2009, 10:44 AM

I got that far but made a mistake when I factored the denominator of the second term. Thanks for the help.

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