# Thread: Simplify and multiply this equation

1. ## Simplify and multiply this equation

I can solve this through substitution since it's multiple choice ($\displaystyle X/(X-1)$, but how is it simplified?

(($\displaystyle 9x^2-4$)$\displaystyle /$($\displaystyle 3x^2-5x+2$)) * ($\displaystyle (9x^4-6x^3+4x^2$)/$\displaystyle 27x^4+8x$)

2. Originally Posted by fcabanski
I can solve this through substitution since it's multiple choice ($\displaystyle X/(X-1)$, but how is it simplified?

(($\displaystyle 9x^2-4$)$\displaystyle /$($\displaystyle 3x^2-5x+2$)) * ($\displaystyle (9x^4-6x^3+4x^2$)/$\displaystyle 27x^4+8x$)
Hi fcabanski,

$\displaystyle \frac{9x^2-4}{3x^2-5x+2}\cdot \frac{9x^4-6x^3+4x^2}{27x^4+8x}$

Let's factor the thing.

$\displaystyle \frac{(3x-2)(3x+2)}{(3x-2)(x-1)}\cdot \frac{x^2(9x^2-6x+4)}{x(27x^3+8)}$

$\displaystyle \frac{(3x-2)(3x+2)}{(3x-2)(x-1)}\cdot \frac{x^2(9x^2-6x+4)}{x(3x+2)(9x^2-6x+4)}$

How's this for a start?

3. I got that far but made a mistake when I factored the denominator of the second term. Thanks for the help.