First,
a = (1 + 2 + 3 + ... + n) / (n^2)
When I try to find the limit of a when n tends to infinity,
I have tried two ways:
1. I converted a to
2 - [(1 / 2) ^ (n) ] and get the value 2.
2. I make it to
a = 1 / n^2 + 2 / n^2 + 3 / n^2 + ... + n/ n^2 and then take the limit.
but this give an answer 0.
Why? I know there must be something wrong.