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Math Help - Tension

  1. #1
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    Tension

    g to be assumed to be 10m/s

    A car of mass 800kg is towing a trailer of mass 400kg up a hill of inclination x where sinx = 1/20. The trailer is connected to the car by a towbar which is parallel to the direction of hte motion. At a given instance, the speed of both vehicle is 7m/s and both accelerating at 0.1ms-2. At this instance the power of the car engine is 14KW and the resistance to the motion of the car is 300N.

    Show the tension in the tow bar is 1220 N

    Resistance to the motion of the trailer..

    Im all confused, i dont seem to understand the concept of tension at all....

    I know P = f s
    so that gives me 14 000/7 = 2000 N

    But it's on an inclined surface so i guess you gotta do something to it...
    considering the resistance is 300N so gotta subtract it right ?
    giving me 1700 N ?
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  2. #2
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    Quote Originally Posted by ramzel View Post
    g to be assumed to be 10m/s

    A car of mass 800kg is towing a trailer of mass 400kg up a hill of inclination x where sinx = 1/20. The trailer is connected to the car by a towbar which is parallel to the direction of hte motion. At a given instance, the speed of both vehicle is 7m/s and both accelerating at 0.1ms-2. At this instance the power of the car engine is 14KW and the resistance to the motion of the car is 300N.

    Show the tension in the tow bar is 1220 N

    Resistance to the motion of the trailer..

    Im all confused, i dont seem to understand the concept of tension at all....

    I know P = f s
    so that gives me 14 000/7 = 2000 N

    But it's on an inclined surface so i guess you gotta do something to it...
    considering the resistance is 300N so gotta subtract it right ?
    giving me 1700 N ?
    P = F v

    F = (14 kW)/(7 m/s) = 2000 N up the hill

    F{net} = ma

    F - T - R - mg sin(x) = ma

    2000 - T - 300 - 800(10)(1/20) = 800(0.1)

    T = 1220 N
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