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Math Help - graphing functions

  1. #1
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    graphing functions

    Hey guys, I need some help on this graphing stuff. Any help is MUCH appreciated.

    1. Sketch f(x) = { -x-3 if x < 0 }{lxl if 0 <or= x <2}{3 if x >or= 2}

    If I'm not mistaken, doesn't the last piece get ignored since it goes against the first two?

    2. f(x) = -(x+2)^3 +1
    a. What type of function is it? <--- i don't really know what she's looking for... maybe a cubing function?
    b. Sketch, showing all intermediate graphs. <---- again, unsure what ALL intermediate would mean...

    3. g(x) = square root(4 - x) +2
    a. Domain <--- this one i think i got, (-inf. , 4)U(4, inf.) right?
    b. find the y-intercept <--- do you do this by setting x = 0?
    c. Sketch, showing all intermediate graphs

    Again, thanks a lot for ANY help at all. Kinda lengthy, sry....
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by leviathanwave View Post
    Hey guys, I need some help on this graphing stuff. Any help is MUCH appreciated.

    1. Sketch f(x) = { -x-3 if x < 0 }{lxl if 0 <or= x <2}{3 if x >or= 2}

    If I'm not mistaken, doesn't the last piece get ignored since it goes against the first two?
    The sketch should look something like that in the attachment (ignore the
    vertical lines they are just an artifact of the plotting software)

    RonL
    Attached Thumbnails Attached Thumbnails graphing functions-gash.jpg  
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by leviathanwave View Post
    2. f(x) = -(x+2)^3 +1
    a. What type of function is it? <--- i don't really know what she's looking for... maybe a cubing function?
    b. Sketch, showing all intermediate graphs. <---- again, unsure what ALL intermediate would mean...
    a) its a cubic.

    b) start with a sketch of y=-x^3, then sketch it translated horizontaly 2
    units to the left to get a sketch of y=-(x+2)^3. Then sketch it translated
    upwards by 1 unit to get a sketch of y-1=-(x+2)^3, or y=-(x+2)^3+1.

    RonL
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  4. #4
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    Quote Originally Posted by leviathanwave View Post
    3. g(x) = square root(4 - x) +2
    a. Domain <--- this one i think i got, (-inf. , 4)U(4, inf.) right?
    b. find the y-intercept <--- do you do this by setting x = 0?
    c. Sketch, showing all intermediate graphs
    a) For this to be defined (as a real number) we need that (4-x)>=0, or
    x<=4, as otherwise the square root does not exists. So the domain here is:

    (-inf, 4]

    b) Yes

    RonL
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