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Math Help - Logs

  1. #1
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    Logs

    If I have Log 6 x-3 = 0 (the 6 should be a small 6 attached to the log) It is not working for some reason!


    How can I solve for x?
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  2. #2
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    Hello,

    \log y=0 \Leftrightarrow y=1, in any base.

    so 6x-3=0 and x=... ?
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  3. #3
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    x = 1/2 or 0.5

    Thanks!
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  4. #4
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    Quote Originally Posted by missyd819 View Post
    If I have Log 6 x-3 = 0 (the 6 should be a small 6 attached to the log) It is not working for some reason!


    How can I solve for x?
    your notation needs some work ...

    if \log_6(x-3) = 0 , then x = 4

    if \log_6{x} - 3 = 0 , then x = 6^3
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  5. #5
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    x-3 should be in the parenthesis, but how do you get 4 then?
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  6. #6
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    do you understand Moo's prior statement?

    Quote Originally Posted by Moo View Post

    \log y=0 \Leftrightarrow y=1, in any base.
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  7. #7
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    No because she had 6x - 3 = 0, so I though x = 1/2. I have no idea how to even start to get close to 4.
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  8. #8
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    \log_6(x-3) = 0

    change to an exponential equation ...

    6^0 = x-3

    what is the value of x?
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  9. #9
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    ok, so x = 4

    Now I have it! Thank you!
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