1. ## Logs

If I have Log 6 x-3 = 0 (the 6 should be a small 6 attached to the log) It is not working for some reason!

How can I solve for x?

2. Hello,

$\displaystyle \log y=0 \Leftrightarrow y=1$, in any base.

so $\displaystyle 6x-3=0$ and x=... ?

3. x = 1/2 or 0.5

Thanks!

4. Originally Posted by missyd819
If I have Log 6 x-3 = 0 (the 6 should be a small 6 attached to the log) It is not working for some reason!

How can I solve for x?
your notation needs some work ...

if $\displaystyle \log_6(x-3) = 0$ , then $\displaystyle x = 4$

if $\displaystyle \log_6{x} - 3 = 0$ , then $\displaystyle x = 6^3$

5. x-3 should be in the parenthesis, but how do you get 4 then?

6. do you understand Moo's prior statement?

Originally Posted by Moo

$\displaystyle \log y=0 \Leftrightarrow y=1$, in any base.

7. No because she had 6x - 3 = 0, so I though x = 1/2. I have no idea how to even start to get close to 4.

8. $\displaystyle \log_6(x-3) = 0$

change to an exponential equation ...

$\displaystyle 6^0 = x-3$

what is the value of $\displaystyle x$?

9. ok, so x = 4

Now I have it! Thank you!