If I have Log 6 x-3 = 0 (the 6 should be a small 6 attached to the log) It is not working for some reason!

How can I solve for x?

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- Aug 20th 2009, 12:32 PMmissyd819Logs
If I have Log 6 x-3 = 0 (the 6 should be a small 6 attached to the log) It is not working for some reason!

How can I solve for x? - Aug 20th 2009, 12:35 PMMoo
Hello,

$\displaystyle \log y=0 \Leftrightarrow y=1$, in any base.

so $\displaystyle 6x-3=0$ and x=... ? - Aug 20th 2009, 01:12 PMmissyd819
x = 1/2 or 0.5

Thanks! - Aug 20th 2009, 01:43 PMskeeter
- Aug 20th 2009, 01:49 PMmissyd819
x-3 should be in the parenthesis, but how do you get 4 then?

- Aug 20th 2009, 01:51 PMskeeter
- Aug 20th 2009, 02:02 PMmissyd819
No because she had 6x - 3 = 0, so I though x = 1/2. I have no idea how to even start to get close to 4.

- Aug 20th 2009, 02:11 PMskeeter
$\displaystyle \log_6(x-3) = 0$

change to an exponential equation ...

$\displaystyle 6^0 = x-3$

what is the value of $\displaystyle x$? - Aug 20th 2009, 02:19 PMmissyd819
ok, so x = 4

Now I have it! Thank you!