# Math Help - Inverse Function

1. ## Inverse Function

If f(x) = the cube root of 2x - 3,

how do I find f^-1 (x)?

2. Hello,

$y=\sqrt[3]{2x-3}=(2x-3)^{1/3}$

Put everything to the power 3, so that it simplifies with 1/3 (recall $(a^b)^c=a^{bc}$)

so $y^3=2x-3$

and... $x=\tfrac{y^3+3}{2}=f^{-1}(y)$

does it look clear to you ?

3. Yes, so much clearer. Silly mistake I just realized I made. Thanks!!