for $\displaystyle f(x) = x^{1/3}$ increasing: (-∞, ∞) Decreasing: ? for decreasing i think its none. idk
Last edited by yoman360; Aug 16th 2009 at 05:54 PM.
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What exactly is your function? Did you mean $\displaystyle y=x^{\frac{1}{3}}$ ? It will be increasing on $\displaystyle \frac{dy}{dx}>0$ and decreasing on $\displaystyle \frac{dy}{dx}<0$
Originally Posted by pickslides What exactly is your function? Did you mean $\displaystyle y=x^{\frac{1}{3}}$ ? It will be increasing on $\displaystyle \frac{dy}{dx}>0$ and decreasing on $\displaystyle \frac{dy}{dx}<0$ I haven't learned that dy/dx stuff yet so that doesn't make sense to me right now. And yes its $\displaystyle f(x)= x^{1/3}$
Originally Posted by yoman360 for $\displaystyle f(x) = x^{1/3}$ increasing: (-∞, ∞) This is correct therefore it cannot be decreasing.
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