lim [(3x^2 + 3x - 18) / (x - 2)] when x ---> 2 I've got [(3x +6)(x - 3)] / (x - 2) but not sure what to do from here.
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Hi brumby_3 Just substitute x = 2 to the limit
Originally Posted by brumby_3 lim [(3x^2 + 3x - 18) / (x - 2)] when x ---> 2 I've got [(3x +6)(x - 3)] / (x - 2) but not sure what to do from here. Your factorisation of the numerator is wrong. You should have checked it by expanding. Fix it. Then cancel the factor common to numerator and denominator. Then substitute x = 2.
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