Originally Posted by
flyinhigh123 The points P(2ap,ap^2) and Q(2aq, aq^2) vary on the parabola x^2=4ay. The chord PQ subtends a right angle at the vertex. The tangents at P and Q meet at T, while the normals at P and Q meet at N
Find the cartesian equation of the locus of N
So in this qs I have already proved that pq = -4 and that T has coordinates (a(p+q),apq) and that N has coordinates (-apq(p+q),a(p^2+pq+q^2+2))
i just need to use the coordinates of N and find the locus, also using T and pq but i keep getting it wrong, if someone could help me, i would REALLY appreciate it, the answer is x^2 = 16a(y-6a)
thankyou !! =D