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Math Help - Limits

  1. #1
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    Limits

    HI,

    I didn't knox how to calculate the following limits:

    1)- \lim_{x\to \frac{\pi}{4}} f(x)=\frac{tanx-1}{\sqrt{2}cosx-1}     .

    2)- \lim_{x\to 0} f(x)=\frac{cosx+cos2x-2}{cos3x+sinx-1}

    Can you help me please?

    And Thank's for anyway.
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  2. #2
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    Quote Originally Posted by lehder View Post
    HI,

    I didn't knox how to calculate the following limits:

    1)- \lim_{x\to \frac{\pi}{4}} f(x)=\frac{tanx-1}{\sqrt{2}cosx-1} .
    Have you herd of L'hospital's rule?

    For \lim_{x\to a} f(x)=\frac{g(x)}{h(x)}

    if \lim_{x\to a} g(x) = \lim_{x\to a} h(x) = 0

    then \lim_{x\to a} f(x)=\frac{g(x)}{h(x)} = \lim_{x\to a} f(x)=\frac{g'(x)}{h'(x)}
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  3. #3
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    Quote Originally Posted by pickslides View Post
    Have you herd of L'hospital's rule?

    For \lim_{x\to a} f(x)=\frac{g(x)}{h(x)}

    if \lim_{x\to a} g(x) = \lim_{x\to a} h(x) = 0

    then \lim_{x\to a} f(x)=\frac{g(x)}{h(x)} = \lim_{x\to a} f(x)=\frac{g'(x)}{h'(x)}
    Thank you very much, i find that 1) = -2
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  4. #4
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    I agree
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  5. #5
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    Quote Originally Posted by pickslides View Post
    I agree

    And the second is egal = 0
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