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Please help me find the domain of the following problems:
1. 5throot(-4+3x)
The function is defined on the interval from _________ to __________
2. 6throot(-4+3x)
The function is defined on the interval from _________ to __________
3. The domain of the function sqrt(x(x-4)) in interval notation is _________
Thanks so much!!
For an "even" root we require that the argument is non-negative. For an "odd" root we don't have that restriction. So the answer to 1 is all real numbers and the answer to 2 isQuote:
Originally Posted by qbkr21
.
3 is a tad more difficult, but all we need do is determine where. This happens for
as you can verify by several means.
-Dan
Except for #3 you must use bracket, also I am unable to figure out how you got #2 could you please explain a bit more?
Yes, the answer for 3 should beQuote:
Originally Posted by qbkr21
because of the
relation. Thank you.
For 2 we require that the argument under the 6th root be non-negative for the same reason we require the same for the square root:is not defined for negative x. (Or if you wish to speak more loosely, a negative x will return an imaginary value.)
So we see that I goofed again. :o The argument of the 6th root isso we require that
or the solution for x is the interval:
.
(I was obviously doing this problem too fast. My apologies!)
-Dan