# Thread: Slope Intercept to Standard Form

1. ## Slope Intercept to Standard Form

I have another problem on my math summer review hoping you can help.

I need to convert this slope intercept equation to standard form(Ax+By=C) where the A is positive.

Equation:
Y=(-1/2)
Y=(13/10)x

EDIT: I also need help with this one, same type of problem.

Y=(13/10)x

2. Hi Mp5xm8

Is this what you mean?

y = - 1/2 ------------------> already in standard form where A = 0, B = 1, C = -1/2

y = (13/10)x
(13/10) x - y = 0 --------> A = (13/10), B = -1, C = 0

or

y = (13/10) x
10 y = 13 x
13 x - 10 y = 0 ----------> A = 13, B = -10, C = 0

3. Hello Mp5xm8
Originally Posted by Mp5xm8
I have another problem on my math summer review hoping you can help.

I need to convert this slope intercept equation to standard form(Ax+By=C) where the A is positive.

Equation:
Y=(-1/2)
Y=(13/10)x

EDIT: I also need help with this one, same type of problem.

Y=(13/10)x
I'm not quite sure what you mean here. Since you mention slope-intercept, I'm guessing that perhaps the intercept is $\displaystyle y = -\tfrac12$, and the slope is $\displaystyle \tfrac{13}{10}$. Is that what you mean?

If so, its '$\displaystyle y = mx + c$' equation is

$\displaystyle y = \tfrac{13}{10}x-\tfrac12$

Multiply both sides by $\displaystyle 10$:

$\displaystyle 10y = 13x - 5$

So the equation in the format you wanted is:

$\displaystyle 13x -10y = 5$