# Slope Intercept to Standard Form

• Aug 10th 2009, 05:06 PM
Mp5xm8
Slope Intercept to Standard Form
I have another problem on my math summer review hoping you can help.

I need to convert this slope intercept equation to standard form(Ax+By=C) where the A is positive.

Equation:
Y=(-1/2)
Y=(13/10)x

EDIT: I also need help with this one, same type of problem.

Y=(13/10)x
• Aug 10th 2009, 07:38 PM
songoku
Hi Mp5xm8

Is this what you mean?

y = - 1/2 ------------------> already in standard form where A = 0, B = 1, C = -1/2

y = (13/10)x
(13/10) x - y = 0 --------> A = (13/10), B = -1, C = 0

or

y = (13/10) x
10 y = 13 x
13 x - 10 y = 0 ----------> A = 13, B = -10, C = 0
• Aug 11th 2009, 02:30 AM
Hello Mp5xm8
Quote:

Originally Posted by Mp5xm8
I have another problem on my math summer review hoping you can help.

I need to convert this slope intercept equation to standard form(Ax+By=C) where the A is positive.

Equation:
Y=(-1/2)
Y=(13/10)x

EDIT: I also need help with this one, same type of problem.

Y=(13/10)x

I'm not quite sure what you mean here. Since you mention slope-intercept, I'm guessing that perhaps the intercept is $y = -\tfrac12$, and the slope is $\tfrac{13}{10}$. Is that what you mean?

If so, its ' $y = mx + c$' equation is

$y = \tfrac{13}{10}x-\tfrac12$

Multiply both sides by $10$:

$10y = 13x - 5$

So the equation in the format you wanted is:

$13x -10y = 5$