Solving exponential equation using a... graph?

**Såxon** · August 9th 2009, 04:49 PM

What am I suppose to look for on the graph, in order to solve this?
Sorry if this seems obvious.
Use a graph to solve the equation 2^-x - 6

**skeeter** · August 9th 2009, 04:56 PM

Originally Posted by Såxon

What am I suppose to look for on the graph, in order to solve this?
Sorry if this seems obvious.
Use a graph to solve the equation 2^-x - 6

is the equation supposed to be

$2^{-x} = 6$

???

**Wesker** · August 9th 2009, 05:08 PM

maybe you mean 2^-x -6=0??

**Såxon** · August 9th 2009, 05:10 PM

oh wow, sorry yes it is (2^-x) - 6 = 0...

**skeeter** · August 9th 2009, 05:15 PM

Originally Posted by Såxon

oh wow, sorry yes it is (2^-x) - 6 = 0...

you could use a graph on a calculator and calculate the root.

or ...

$2^{-x} = 6$

$\ln(2^{-x}) = \ln(6)$

$-x \cdot \ln(2) = \ln(6)$

$x = -\frac{\ln(6)}{\ln(2)}$

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