# Math Help - find the formula for the function

1. ## find the formula for the function

f(x)= x^2+1 g(x)=1/(x-3)

f(g(x))

so (1/(x-3))^2 +1

and from there i am lost on this problem.

thanks

2. Originally Posted by valvan
f(x)= x^2+1 g(x)=1/(x-3)

f(g(x))

so (1/(x-3))^2 +1

and from there i am lost on this problem.

thanks

You also don't really need to go any further, unless you are asked to write it down in a different way...

$f(g(x))=\left(\frac{1}{x - 3}\right)^2 + 1$

$= \frac{1}{(x - 3)^2} + 1$

$= \frac{1}{x^2 - 6x + 9} + \frac{x^2 - 6x + 9}{x^2 - 6x + 9}$

$= \frac{x^2 - 6x + 10}{x^2 - 6x + 9}$.

This is about as far as you can go, but like I said, what you had so far is also correct.

3. ok thanks, just got confused over how far i should go, this clears it up for me.