f(x)= √3-x. Find expression for f^-1(x). My answer is x=√3-y, y≠ all real numbers ≥ 3 Is that correct? Thanks
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Originally Posted by live_laugh_luv27 f(x)= √3-x. Find expression for f^-1(x). My answer is x=√3-y, y≠ all real numbers ≥ 3 Is that correct? Thanks is the function $\displaystyle f(x) = \sqrt{3} - x$ or $\displaystyle f(x) = \sqrt{3-x}$ ?
sorry, I don't know how to type that on the computer
Originally Posted by live_laugh_luv27 sorry, I don't know how to type that on the computer then you need to learn ... at least use parentheses as grouping symbols. inverse ... $\displaystyle y = \sqrt{3-x}$ , $\displaystyle x \le 3$ $\displaystyle x = \sqrt{3-y}$ $\displaystyle x^2 = 3-y$ $\displaystyle y = 3 - x^2$ , $\displaystyle x \ge 0$
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