sec2xdx/cos^2[2x](sex2x-1)
Thanks!
Hello, honestliar!
sa-ri-ga-ma gave you a big hint?
Was it enough?
SinceIntegrate: .
. . we have: .
The first three terms have standard integration formulas.
For the fraction: .
Multiply by
Multiply by
. .
. .
And we have: .
. . which also have standard integration formulas.