Can someone give me a hand?
The problem is Log3 (3x-2)=3
I have A= 3
and then I have 3^3 (3x-2)
I can't figure out how to sove it. I know it is a fraction but can anyone tell me what it is or how to solve it?
What is the easiest way to figure it out? obviously 3 * 10 =30 -2 would be 29...so that is not the answer. I know this may sound dumb but how do i then solve for x? I am very new to calculus. I don't need you to give me the answer if you rather not..but can you direct me a little further? thank you..
Just as you gave me the answer I found an example in my text. But I did it the other way and got 3/29 not 29/3. Thank you. I know i have a long way to go to learn..but I am honestly trying hard. THanks and I am sure i will be having more questions.