who would you factor this?

k^3+6k^2+11k+6

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- July 29th 2009, 06:37 PMjordangiscoolFactoring a cubic function
who would you factor this?

k^3+6k^2+11k+6 - July 29th 2009, 06:42 PMVonNemo19
By the rational zero theorem

- July 29th 2009, 07:10 PMStroodle
This should help you: The Factor Theorem

- July 29th 2009, 07:49 PMVonNemo19
You're not responding so I'll take that to mean that you need an extra push.

The rational zero theorem basically states that a polynomial of the form has rational zeros, then they must be given by the quotient of the divisors of divided by the divisors of .

So, begin by listing all of the divisors of the constant term:

Then list the divisors of the leading coefficient:

So, therefore, the possible zeros of your are .

So, now you can test these values by substition, or synthetic division. Now understand that (by the factor theorem as stroodle posted) if x=c is a zero of f(x), then is a factor of f(x). - July 30th 2009, 05:00 AMDeMath