Determine the equation of line g which passes through point A(1,-1,3) and is parallel to the x-axis,

Letting $\displaystyle \vec u$ be the direction vector of line g,

$\displaystyle \vec u=(1,0,0)$ (Why??)

Printable View

- Jul 27th 2009, 06:38 PMchengbinParametric equations
Determine the equation of line g which passes through point A(1,-1,3) and is parallel to the x-axis,

Letting $\displaystyle \vec u$ be the direction vector of line g,

$\displaystyle \vec u=(1,0,0)$ (Why??) - Jul 27th 2009, 06:49 PMsongoku
Because the line g is parallel to the x-axis, the direction will be (1,0,0).

The value of the direction is on the x-direction only, leaving the others zero - Jul 28th 2009, 04:15 AMdhiab
Hello Thank you This the solution :

The line is definite by :http://mathramz.com/xyz/latexrender/...edc6222471.png

But :

http://mathramz.com/xyz/latexrender/...ac5d367b00.png

THE**Parametric equations IS :**

http://mathramz.com/xyz/latexrender/...5ba8877fc3.png - Jul 28th 2009, 04:42 AMchengbin
- Jul 28th 2009, 11:46 PMsongoku
You can choose x = 2, 3, 1/3, etc..

let x = 2

$\displaystyle \vec u = (2,0,0) = 2 (1,0,0)$

let x = 3

$\displaystyle \vec u = (3,0,0) = 3 (1,0,0)$

For the direction of a vector, usually the simplest form is used which is (1,0,0)