The question is
log_{2}(x+1)≤3
then a<x≤b.
What are a and b?
How do I solve this?
I can solve for b which is 7. But how do I solve for a?
Hello,
The logarithm (in any base) is defined only over $\displaystyle (0,\infty)$
So 1+x has to be > 0
This makes x>-1 (a=-1)
Then, we know that the logarithm is an increasing function.
So $\displaystyle \log_2(1+x)\leq 3 \Leftrightarrow 1+x \leq 2^3$
so b=...