The question is log2(x+1)≤3
What are a and b?
How do I solve this?
I can solve for b which is 7. But how do I solve for a?
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The logarithm (in any base) is defined only over
So 1+x has to be > 0
This makes x>-1 (a=-1)
Then, we know that the logarithm is an increasing function.
I didn't know that.
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