The question is log_{2}(x+1)≤3 then a<x≤b. What are a and b? How do I solve this? I can solve for b which is 7. But how do I solve for a?
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Hello, The logarithm (in any base) is defined only over So 1+x has to be > 0 This makes x>-1 (a=-1) Then, we know that the logarithm is an increasing function. So so b=...
Thanks. I didn't know that.
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