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Math Help - logarithm conversion

  1. #1
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    logarithm conversion

    I want to rewrite \ln x to (something) \ln 3x.

    Is that possible?

    For example, if I want to rewrite x^2 to (something) 2x^2, it becomes \frac {1}{2}*2x^2
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  2. #2
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     ln(x) = - ln(3)+ ln(3x)
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  3. #3
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    Quote Originally Posted by pickslides View Post
     ln(x) = - ln(3)+ ln(3x)
    Do you mind showing the logic behind this conversion? Thank you.

    Also, is it possible to rewrite it with only 1 term instead of 2?
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  4. #4
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    I don't know if it can be done with 1 term.

    The logic behind my post is simply the addition of logs law, it is:

    ln(a) + ln(b) = ln(a\times b)

    ln(b)  = - ln(a) + ln(a\times b)

    In your case

    ln(x) + ln(3) =  ln(3x)

    ln(x) = - ln(3)+ ln(3x)
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  5. #5
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    Looks like I was late.

    I got how the conversion works on my bed, I got up to tell you I got it and don't bother explaining it. Thanks anyways.
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  6. #6
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    Not to worry. Good luck!
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