I want to rewrite $\displaystyle \ln x$ to (something) $\displaystyle \ln 3x$.
Is that possible?
For example, if I want to rewrite $\displaystyle x^2$ to (something) $\displaystyle 2x^2$, it becomes $\displaystyle \frac {1}{2}*2x^2$
I want to rewrite $\displaystyle \ln x$ to (something) $\displaystyle \ln 3x$.
Is that possible?
For example, if I want to rewrite $\displaystyle x^2$ to (something) $\displaystyle 2x^2$, it becomes $\displaystyle \frac {1}{2}*2x^2$
I don't know if it can be done with 1 term.
The logic behind my post is simply the addition of logs law, it is:
$\displaystyle ln(a) + ln(b) = ln(a\times b)$
$\displaystyle ln(b) = - ln(a) + ln(a\times b)$
In your case
$\displaystyle ln(x) + ln(3) = ln(3x)$
$\displaystyle ln(x) = - ln(3)+ ln(3x)$