# Thread: Equation of Graph with asymptotes

1. ## Equation of Graph with asymptotes

What is the equation for this graph? How did you get your answer?

2. Originally Posted by Coolman
What is the equation for this graph? How did you get your answer?

Hints:

Spoiler:
1. Note that $\displaystyle x=-3$ and $\displaystyle x=4$ are vertical asymptotes. (Use this to create the denominator of the rational function)

2. As $\displaystyle x\to-\infty$, the function will approach the horizontal asymptote $\displaystyle y=0$

3. $\displaystyle f(5)=0$

3. I got...

f(x) = 1/(x+3)(x-4)

Is it right?

4. Perhaps this is the graph of this function $\displaystyle y = - \frac{1}{{\left( {x + 3} \right)\left( {x - 4} \right)}}.$

5. Originally Posted by DeMath
Perhaps this is the graph of this function $\displaystyle y = - \frac{1}{{\left( {x + 3} \right)\left( {x - 4} \right)}}.$
This doesn't prove true for the graph's show that f(5)=0,

So I think the equation should be;

$\displaystyle y = \frac{(x-5)}{(x+3)(x-4)}$