Results 1 to 5 of 5

Math Help - Equation of Graph with asymptotes

  1. #1
    Newbie
    Joined
    Jul 2009
    Posts
    20

    Equation of Graph with asymptotes

    What is the equation for this graph? How did you get your answer?


    Follow Math Help Forum on Facebook and Google+

  2. #2
    Rhymes with Orange Chris L T521's Avatar
    Joined
    May 2008
    From
    Chicago, IL
    Posts
    2,844
    Thanks
    3
    Quote Originally Posted by Coolman View Post
    What is the equation for this graph? How did you get your answer?


    Hints:

    Spoiler:
    1. Note that x=-3 and x=4 are vertical asymptotes. (Use this to create the denominator of the rational function)

    2. As x\to-\infty, the function will approach the horizontal asymptote y=0

    3. f(5)=0
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Jul 2009
    Posts
    20
    I got...

    f(x) = 1/(x+3)(x-4)

    Is it right?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member DeMath's Avatar
    Joined
    Nov 2008
    From
    Moscow
    Posts
    473
    Thanks
    5
    Perhaps this is the graph of this function y =  - \frac{1}{{\left( {x + 3} \right)\left( {x - 4} \right)}}.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Member
    Joined
    Mar 2009
    From
    Alberta
    Posts
    173
    Quote Originally Posted by DeMath View Post
    Perhaps this is the graph of this function y =  - \frac{1}{{\left( {x + 3} \right)\left( {x - 4} \right)}}.
    This doesn't prove true for the graph's show that f(5)=0,

    So I think the equation should be;

    y = \frac{(x-5)}{(x+3)(x-4)}
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 7
    Last Post: August 5th 2011, 01:30 PM
  2. Replies: 2
    Last Post: July 28th 2011, 10:50 AM
  3. Replies: 5
    Last Post: December 28th 2010, 12:22 AM
  4. I found asymptotes but can't sketch graph
    Posted in the Pre-Calculus Forum
    Replies: 5
    Last Post: December 3rd 2009, 04:47 PM
  5. Replies: 3
    Last Post: April 15th 2009, 02:54 PM

Search Tags


/mathhelpforum @mathhelpforum