Given f(x) = (1/x + 2) + 3, find the inverse function.
MY WORK:
Let y = f(x).
y = (1/x + 2) + 3
Switch x and y.
x = (1/y + 2) + 3
Multiply both sides by (y+2).
I ended up with
xy + 2x = 3y + 7
I then subtracted 3y and 2x from both sides.
xy - 3y = -2x + 7
I factored out a y from the left side.
y(x - 3) = -2x + 7
I finally divided both sides by (x - 3).
y = (-2x + 7)/(x - 3)
Then y becomes f^(-1) x
f^(-1) x = (-2x + 7)/(x - 3)
Is the right?


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