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Thread: domain range

  1. #1
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    domain range

    find the domain of

    $\displaystyle g(x)=\frac{2x+3}{3x-4}$

    find the range of

    $\displaystyle
    h(x)=\frac{1}{x^2-9}$
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  2. #2
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    Smile

    hello
    for the first one you should have $\displaystyle 3x-4\neq 0$ which means $\displaystyle x\neq \frac{4}{3}$.
    so the domain is $\displaystyle \mathbb{D}= \mathbb{R}\setminus \left \{ \frac{4}{3} \right \}$
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  3. #3
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    The OP already posted this question in this thread: http://www.mathhelpforum.com/math-he...symptotes.html .


    01
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  4. #4
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    for the second one,you have $\displaystyle x^{2}\geq 0\Leftrightarrow x^{2}-9\geq -9\Leftrightarrow \frac{1}{x^{2}-9}\leq -\frac{1}{9}$and so the range is $\displaystyle (-\infty,-\frac{1}{9}]$
    (still need confirmation)
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