# Math Help - domain range

1. ## domain range

find the domain of

$g(x)=\frac{2x+3}{3x-4}$

find the range of

$
h(x)=\frac{1}{x^2-9}$

2. hello
for the first one you should have $3x-4\neq 0$ which means $x\neq \frac{4}{3}$.
so the domain is $\mathbb{D}= \mathbb{R}\setminus \left \{ \frac{4}{3} \right \}$

3. The OP already posted this question in this thread: http://www.mathhelpforum.com/math-he...symptotes.html .

01

4. for the second one,you have $x^{2}\geq 0\Leftrightarrow x^{2}-9\geq -9\Leftrightarrow \frac{1}{x^{2}-9}\leq -\frac{1}{9}$and so the range is $(-\infty,-\frac{1}{9}]$
(still need confirmation)