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Math Help - sum

  1. #1
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    sum

    hi

    Am i correct to think

    \Sigma k^3 = \Sigma k^2 \times k = \Sigma k^2 \times \Sigma k, \forall k?

    help please
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  2. #2
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    Quote Originally Posted by 1cookie View Post
    Am i correct to think
    \Sigma k^3 = \Sigma k^2 \times k = \Sigma k^2 \times \Sigma k, \forall k?
    \sum\limits_{k = 1}^3 {k^3 }  = 36\;,\;\sum\limits_{k = 1}^3 {k^2 }  = 14\;\& \;\sum\limits_{k = 1}^3 k  = 6

    Now what do you think?
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  3. #3
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    Quote Originally Posted by Plato View Post
    \sum\limits_{k = 1}^3 {k^3 }  = 36\;,\;\sum\limits_{k = 1}^3 {k^2 }  = 14\;\& \;\sum\limits_{k = 1}^3 k  = 6

    Now what do you think?

    ...hmm, clearly 14 \times 6 \neq  36


    i see your point Plato!
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