The graph of $\displaystyle y=sqrt(3x-x^2)$ is given. Use transformations to create a function whose graph is as shown.
1.)
If I had $\displaystyle y=\sqrt{x}$. To flip it through the x axis I'd tack on a negative like so
$\displaystyle y=-\sqrt{x}$
If I wanted to slide it to the left 4 units I'd add four to the variable like this
$\displaystyle y=-\sqrt{(x+4)}$
If I then wanted it to shift down a unit I'd add a constant (subtract in this case)
$\displaystyle y=-\sqrt{(x+4)}-1$
Get it?
Ah I didn't get it right
this is what i did!
$\displaystyle y= sqrt(3x-x^2)$
$\displaystyle y= sqrt(-(3x-x^2))$
$\displaystyle y= -(sqrt(-(3x-x^2)))$
$\displaystyle y= -(sqrt(-(3x-x^2+1)))-1$
My answer: $\displaystyle y= - sqrt(-3x+x^2+1) - 1$
correct answer: $\displaystyle y=-sqrt(-x^2-5x-4)-1$
what did I do incorrectly?