Complex Zeros in polynomials
I need a little help with this please:
Use the given zero to find the remaining zeros of the polynomial:
h(x) = x^4 - 9x^3 + 21x^2 +21x -130; zero: 3-2i
Now i kno all about the zeros when complex existing with their conjugates, i know all about factoring using the different rules and theorems. Had this been a real root, i would've had to divide using long division and testing for roots to factor further, but with this complex one, i am not sure how to do this. Can long division be done on a complex root??? I am not seeing the way of this one. I did one before that had a zero of -2i, but now that the 3 is there i am not sure what to do. Can i get some help please????
Thanks a lot. (Happy)