What are e and p here??
To identify graph, try to convert in x-y cordinates.
Spoiler:
Having a little trouble with where to go with this problem.
Identify the graph of the polar equation r = 3/(4-3cosθ)
3/4/(1-(3/4)cos θ,
e = -3/4
ep = 3/4
3p = 3/4
p = 1/4
Did i get these right? and if so how do i go from here to identify the graph?
I think θ= p/2 at r = 3/4/(1-3/4) = 3 so the graph runs through (p/2,3) right? What from here?
e is the eccentricity and |p| is the distance between the focus and the directrix.
The form we are interested in is
The denominator is , which means that it has a vertical directrix to the left of the pole.
e = 3/4 < 1, so the conic is an ellipse.
The numerator is ep = 3/4, so p = 1 (not 1/4).
No, at , , soI think θ= p/2 at r = 3/4/(1-3/4) = 3 so the graph runs through (p/2,3) right? What from here?
From here, you might as well find r at the other quadrantal angles.
When ,
When ,
When ,
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