I need to solve the following equation:

10^(2X+3) = 280

To express in logarithmic, I know I need to do the following:

log(10)^280 = 2X+3

At this point I'm not sure where to go. I can move the three over to the left:

(log(10)^280) - 3 = 2X

Then divide by two:

((log(10)^280) - 3))/2 = X

I get -.276 = X, but I feel like I'm missing a step in determining the answer. Did I do the steps correctly to come to this answer or is something missing?