I need to solve the following equation:
10^(2X+3) = 280
To express in logarithmic, I know I need to do the following:
log(10)^280 = 2X+3
At this point I'm not sure where to go. I can move the three over to the left:
(log(10)^280) - 3 = 2X
Then divide by two:
((log(10)^280) - 3))/2 = X
I get -.276 = X, but I feel like I'm missing a step in determining the answer. Did I do the steps correctly to come to this answer or is something missing?