# Thread: Finding the equation of the line.....

1. ## Finding the equation of the line.....

I feel like I should know this by now

Can someone please help with this PreCal question?

Find the equation of the line that satisfies the given conditions:

$\displaystyle x-intercept = 1$
$\displaystyle y-intercept = -3$

I'm pretty sure that the equation $\displaystyle y-y_{1}=m(x-x_{2})$ is used but I cannot find out how to obtain the slope $\displaystyle (m)$. Thanks in advance for the help.

-Jerry

2. Originally Posted by Monkee
I feel like I should know this by now

Can someone please help with this PreCal question?

Find the equation of the line that satisfies the given conditions:

$\displaystyle x-intercept = 1$
$\displaystyle y-intercept = -3$

I'm pretty sure that the equation $\displaystyle y-y_{1}=m(x-x_{2})$ is used but I cannot find out how to obtain the slope $\displaystyle (m)$. Thanks in advance for the help.

-Jerry
The two points you have been given are

$\displaystyle (x_1, y_1) = (1, 0)$ and $\displaystyle (x_2, y_2) = (0, -3)$.

Can you work out $\displaystyle m = \frac{y_2 - y_1}{x_2 - x_1}$?

3. Originally Posted by Monkee
I feel like I should know this by now

Can someone please help with this PreCal question?

Find the equation of the line that satisfies the given conditions:

$\displaystyle x-intercept = 1$
$\displaystyle y-intercept = -3$

I'm pretty sure that the equation $\displaystyle y-y_{1}=m(x-x_{2})$ is used but I cannot find out how to obtain the slope $\displaystyle (m)$. Thanks in advance for the help.

-Jerry
x-intercept is 1...which means that line passes through (1,0)
y-intercept is -3...which means that line passes through (0,-3)

with the help of these two points, you can find slope(m).

Spoiler:

$\displaystyle m=\frac{-3-0}{0-1}$
$\displaystyle m=3$

4. Thanks guys! My girlfriend actually figured it out just as you guys replied. Thanks again!!!

5. That's what girlfriends are for!