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Math Help - Finding the equation of the line.....

  1. #1
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    Finding the equation of the line.....

    I feel like I should know this by now


    Can someone please help with this PreCal question?

    Find the equation of the line that satisfies the given conditions:

    x-intercept = 1
    y-intercept = -3

    I'm pretty sure that the equation y-y_{1}=m(x-x_{2}) is used but I cannot find out how to obtain the slope (m). Thanks in advance for the help.

    -Jerry
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  2. #2
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    Quote Originally Posted by Monkee View Post
    I feel like I should know this by now


    Can someone please help with this PreCal question?

    Find the equation of the line that satisfies the given conditions:

    x-intercept = 1
    y-intercept = -3

    I'm pretty sure that the equation y-y_{1}=m(x-x_{2}) is used but I cannot find out how to obtain the slope (m). Thanks in advance for the help.

    -Jerry
    The two points you have been given are

    (x_1, y_1) = (1, 0) and (x_2, y_2) = (0, -3).


    Can you work out m = \frac{y_2 - y_1}{x_2 - x_1}?
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  3. #3
    Super Member malaygoel's Avatar
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    Quote Originally Posted by Monkee View Post
    I feel like I should know this by now


    Can someone please help with this PreCal question?

    Find the equation of the line that satisfies the given conditions:

    x-intercept = 1
    y-intercept = -3

    I'm pretty sure that the equation y-y_{1}=m(x-x_{2}) is used but I cannot find out how to obtain the slope (m). Thanks in advance for the help.

    -Jerry
    x-intercept is 1...which means that line passes through (1,0)
    y-intercept is -3...which means that line passes through (0,-3)

    with the help of these two points, you can find slope(m).

    Spoiler:

    m=\frac{-3-0}{0-1}
    m=3
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    Thanks guys! My girlfriend actually figured it out just as you guys replied. Thanks again!!!
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