The angle is defined at quadrant 1 and it's given that tanx=(11)^(1/2)/5
Find cosx=
cscx=
Hello HMV \tan x = \tfrac{\sqrt{11}}{5}" alt="\tan x = \tfrac{\sqrt{11}}{5}" />
Since the angle is in the first quadrant, it's an acute angle. So you can draw a right-angled triangle where the opposite side to angle is and the adjacent .
So the
Can you complete it now?
Grandad