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Math Help - One more question..

  1. #1
    Newbie
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    Jun 2009
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    One more question..

    How would I go about converting intensity to magnitude? (earthquakes)

    Richter of 6.1 = 1,258,925.412

    But, I am unable to do the opposite! >.<
    Intensities:
    :39,877,000
    :12,589,000
    :251,200

    If you'd use one for an example, that would be greatly appreciated.
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  2. #2
    Member
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    May 2008
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    Melbourne Australia
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    Quote Originally Posted by pinnacle2009 View Post
    How would I go about converting intensity to magnitude? (earthquakes)

    Richter of 6.1 = 1,258,925.412

    But, I am unable to do the opposite! >.<
    Intensities:
    :39,877,000
    :12,589,000
    :251,200

    If you'd use one for an example, that would be greatly appreciated.

    You have found that:
    10^{6.1} = 1,258,925.412

    What you now need to do is find x when:
    10^x = 39,877,000

    Take the log (base 10) of both sides of the equation to get:

    log(10^x) = log(39,877,000)

    \therefore x = log(39,877,000) = 7.6
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  3. #3
    Super Member
    Joined
    May 2009
    Posts
    527
    The formula is
    R = \log \frac{I}{I_0}
    where I_0 is the intensity of a zero-level earthquake. Looking at this:

    Richter of 6.1 = 1,258,925.412
    I'm assuming that you're assuming that the intensity of a zero-level earthquake is 1.

    So, for an intensity of 39,877,000,
    R = \log 39,877,000 \approx 7.6.

    You can do the other two.


    01

    EDIT: Beaten to it by Kiwi Dave!
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