# Math Help - Graphing y= 2cot(2x-pi/2)

1. ## Graphing y= 2cot(2x-pi/2)

Graph y= 2cot(2x-pi/2)

State the period and phase shift.

2. I'll skip the graphing part. Note that
$y = 2\cot \left(2x-\frac{\pi}{2}\right) = 2\cot \left(2\left(x-\frac{\pi}{4}\right)\right)$.

The basic form of the cotangent function is $y = a\cot (b(x - h)) + k$. The period would be $\frac{\pi}{|b|}$, and the phase shift is h.

Therefore, in your problem, the period would be $\frac{\pi}{2}$ and the phase shift would be $\frac{\pi}{4}$.

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