I did log_{2}(-1)1/9=log_2x^2 (-1/9)=x^2 ? cant take root of a negative and even If I did I get the wrong answer.
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Originally Posted by brentwoodbc I did log_{2}(-1)1/9=log_2x^2 (-1/9)=x^2 ? cant take root of a negative and even If I did I get the wrong answer. Using change of base you can write log(1/9)/log(1/2) = 2logx/log2. 1/2*log(1/9)/-log(2) = log x/log2 -log(1/3) = log x log3 = log x
$\displaystyle \log_{\frac{1}{2}}{\frac{1}{9}} = -\log_2{\frac{1}{9}} = \log_2{9}$
I thought my way should work, so ya the answer is +3 but I thought it could only be+ I guess because a negative number squared is a positive
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