1. ## logs

I did log_{2}(-1)1/9=log_2x^2
(-1/9)=x^2
? cant take root of a negative and even If I did I get the wrong answer.

2. Originally Posted by brentwoodbc

I did log_{2}(-1)1/9=log_2x^2
(-1/9)=x^2
? cant take root of a negative and even If I did I get the wrong answer.
Using change of base you can write
log(1/9)/log(1/2) = 2logx/log2.
1/2*log(1/9)/-log(2) = log x/log2
-log(1/3) = log x
log3 = log x

3. $\log_{\frac{1}{2}}{\frac{1}{9}} = -\log_2{\frac{1}{9}} = \log_2{9}$

4. I thought my way should work, so ya the answer is +3 but I thought it could only be+ I guess because a negative number squared is a positive