How do I work out the implied domains for and also for

Thanks heaps

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- June 14th 2009, 02:02 AMStroodleImplied Domain
How do I work out the implied domains for and also for

Thanks heaps - June 14th 2009, 03:11 AMmr fantastic
- June 14th 2009, 03:29 AMStroodle
Thanks. I get the first one now, but my problem is solving

I'm getting so is the domain R\{-2} ?

THanks for your help

What's the command for squiggly brackets in latex btw? :) - June 14th 2009, 03:38 AMAMI
I think for the first one there are no restrictions, because so the implied domain should be .

- June 14th 2009, 03:54 AMStroodle
For the first one I'm getting

- June 14th 2009, 04:00 AMAMI
- June 14th 2009, 04:09 AMRaoh
hi

for the first one :

for the second : - June 14th 2009, 04:10 AMStroodle
Hmm. I'm definitely doing something wrong here. I'm getting

Which must be wrong. But the answer is definitely R/{-1} - June 14th 2009, 04:20 AMStroodle
- June 14th 2009, 04:23 AMmr fantastic
Incorrect. If then you have just committed the cardinal sin of dividing by zero when you do this. The domain is all real numbers EXCEPT . The graph of has a 'hole' at .

Incorrect. See above.

Your bracket notation needs some minor corrections:

- June 14th 2009, 04:27 AMmr fantastic
- June 14th 2009, 04:36 AMRaoh
(sorry about later)

for the second one : study the sign of and then study

and see where is positive. - June 14th 2009, 04:43 AMStroodle
Awesome. Thanks. I made some pretty silly errors there :)

- June 14th 2009, 05:35 AMAMI
- June 14th 2009, 06:14 AMAMI
Oh, nevermind, I think I got it.

I think I was saying something like*"we don't need any restrictions for the function**because it's equal to*", which is obviously false :mad:

Sorry about that..(Speechless)