# Math Help - (z-1)^2 < 1 is..

1. ## (z-1)^2 < 1 is..

The set of real numbers z such that $(z-1)^2 < 1$ is an open interval in the form (a,b). Express a and b as integers.

2. move 1 to the left side and factor to
(x-2)x < 0
(0,2) is the interval. see the other post for reasoning. g luck!

3. Originally Posted by apcalculus
move 1 to the left side and factor to
(x-2)x < 0
(0,2) is the interval. see the other post for reasoning. g luck!
Thanks I got it now
$(z-1)^2 < 1$
$z^2-2z+1 < 1$
$z^2-2z < 0$
z(z-2) < 0
z<0
z-2<0 -----> z<2
(0,2)

4. hi
$z(z-2)< 0$ needs $z > 0$ and $z-2 < 0$
the interval is indeed $]0,2[$

<, z12