I got a problem with solving this problem on circles....

The sides of a triangle lie on the lines 3x+y-5=0, x - 3y-1 = 0 and x+3y+7=0 find the equation of the circle inscribed in the triangle..

Helppp ... How am i going to use angle bisector in this problem?

Answer at back of book:

(x-\frac{5}{6})^2 + (y+\frac{4}{3})^2 = \frac{529}{360}

Thanks and Merry Christmas All! :)

Btw hows latex doin is broken again?