hi-
i think u are on the right track.
continue.
Just a step and u are there!
Sort of lost on how to continue...
Prove that the following formula is true for all n using inductive reasoning 3 + 7 + 11 + .... +(4n - 1) = n(2n + 1)
n = 1 is true
assume k1 is true? (4k - 1) = k(2k + 1)
now to prove k + 1
[4(k+1) - 1] + (4k - 1) = k(2k + 1) + [4(k+1) - 1]
Would someone mind showing me where to go from here?
I've added some parts that should be there -- I can't tell if you omitted them for less typing, or weren't sure that they should be there.
You want to show that the last thing you typed: k(2k + 1) + [4(k+1) - 1] is equal to (k+1)(2(k+1) + 1), for the inductive statement to be true.
Show that as Amer did: