firstly it is important to know that
for example
and = a massive number.
For calculating
make sure you cancel as many terms as you can to make life easy
i.e.
Im a little confused on how to do this problem.
Use the definition of [n] to show that [ 6 ] + [6] = [7] for all integers 1≤r≤6
[r ] [r-1] [r] = [ r]
The formula/definition is n!/r!(n - r!) am i correct? Help or an explanation of how to use this formula would be great! Thanks!!
[6] + [6] = [7] for all integers 1≤r≤6.
[r-1] [r] [r]
I think i understand what your saying, however i am still confused as how to show the proof in the above statement...
my work:
6!/(r!-1(6-r!-1)) + 6!/(r!(6-r!)) = 7!/r!(7-r!)
Is this the correct way of setting this up? If so, where do i go from here?
Im confused, but thanks a lot for your time!