# Thread: need help on solving zero equations

1. ## need help on solving zero equations

I'm stuck:

a. 4(x squared) + 12x + 3 = 0

b. 2x + 1 = 5 divided by (x + 2)

c. [(x + 1) divided by x ] - [x divided by (x + 1)] = 0

2. Originally Posted by 5441lk
I'm stuck:

a. 4(x squared) + 12x + 3 = 0

b. 2x + 1 = 5 divided by (x + 2)

c. [(x + 1) divided by x ] - [x divided by (x + 1)] = 0

Here ya go

$4x^2+12x+3=0$

using the quadratic formula let a=4, b=12 and c=3 we have

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

so

$x=\frac{-12\pm\sqrt{(12)^2-4(4)(c)}}{2(4)}$

you can do the rest.

As for the next one

$2x+1=\frac{5}{x+2}$

multiply both sides by (x+2) and then subtract by 5

$(x+2)(2x+1)-5=0$

multiply and simplify

$2x^2+5x-3=0$ and use the quadratic formula. I'll leave the last one to you

Hint : find a common denominator and then multiply both sides of the equation by it.

3. for equations in the form $ax^2+bx+c = 0$ to find zeros you can apply

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

For $4x^2+12x+3 = 0$ you make $a=4, b=12,c=3$ therefore

$x=\frac{-12\pm\sqrt{12^2-4\times 4\times 3}}{2\times 4}$

go fot it!