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Math Help - need help on solving zero equations

  1. #1
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    Question need help on solving zero equations

    I'm stuck:

    a. 4(x squared) + 12x + 3 = 0

    b. 2x + 1 = 5 divided by (x + 2)

    c. [(x + 1) divided by x ] - [x divided by (x + 1)] = 0
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  2. #2
    No one in Particular VonNemo19's Avatar
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    Quote Originally Posted by 5441lk View Post
    I'm stuck:

    a. 4(x squared) + 12x + 3 = 0

    b. 2x + 1 = 5 divided by (x + 2)

    c. [(x + 1) divided by x ] - [x divided by (x + 1)] = 0

    Here ya go

    4x^2+12x+3=0

    using the quadratic formula let a=4, b=12 and c=3 we have

    x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

    so

    x=\frac{-12\pm\sqrt{(12)^2-4(4)(c)}}{2(4)}

    you can do the rest.

    As for the next one

    2x+1=\frac{5}{x+2}

    multiply both sides by (x+2) and then subtract by 5

    (x+2)(2x+1)-5=0

    multiply and simplify

    2x^2+5x-3=0 and use the quadratic formula. I'll leave the last one to you

    Hint : find a common denominator and then multiply both sides of the equation by it.
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  3. #3
    Master Of Puppets
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    for equations in the form ax^2+bx+c = 0 to find zeros you can apply

    x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

    For 4x^2+12x+3 = 0 you make a=4, b=12,c=3 therefore

    x=\frac{-12\pm\sqrt{12^2-4\times 4\times 3}}{2\times 4}

    go fot it!
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