I need to find the magnitude and direction angle for the vector A + B given A = <-3,2> and B = <1,4>. Thank you in advance.
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Originally Posted by Neversh I need to find the magnitude and direction angle for the vector A + B given A = <-3,2> and B = <1,4>. Thank you in advance. $\displaystyle A+B=<-2,6>$ $\displaystyle ||<-2,6>||=\sqrt{(-2)^2+6^2}=\sqrt{4+36}=2\sqrt{10}$ Since the vector is in the 2nd quadrant we get $\displaystyle \theta=\tan^{-1}\left( \frac{6}{-2}\right)+\pi$
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