Take this one for example 1/3log7^x +13log7^y - 5log5^z How would I reduce this to a single logarithm?
Follow Math Help Forum on Facebook and Google+
you should know that apply these two formula you will get the answer
Originally Posted by Amer you should know that apply these two formula you will get the answer If only it was that easy for me. Using that I can get it down to log7(x^(1/3)*y^(13)) -5log5^z What is throwing me off is the different bases. 5 and 7. And then the different variables x,y, and a third variable z.
Originally Posted by bilbobaggins Take this one for example 1/3log7^x +13log7^y - 5log5^z How would I reduce this to a single logarithm? see
Originally Posted by Amer see Oh, I just realized that before I refreshed and saw your response. Thanks.
Last edited by bilbobaggins; June 5th 2009 at 01:34 PM.
the number the is multiplies with the Logarithm is a power for what is inside it see this so now
Originally Posted by Amer the number the is multiplies with the Logarithm is a power for what is inside it see this so now So you can just take the base out of the log and put it in a fraction? Thanks, I didn't know that.
Originally Posted by bilbobaggins So you can just take the base out of the log and put it in a fraction? No. Are you saying that your 7s were actually the bases and the stuff you presented as exponents were really arguments?
Originally Posted by bilbobaggins Take this one for example 1/3log7^x +13log7^y - 5log5^z How would I reduce this to a single logarithm? If those numbers after "log" are the base (ie: then you can combine the first two terms using the laws written by Amer Use the change of base rule on this new term and the second term to make them the same base
Originally Posted by e^(i*pi) If those numbers after "log" are the base (ie: then you can combine the first two terms using the laws written by Amer Use the change of base rule on this new term and the second term to make them the same base So (log(x^1/3*y^13)/log7) - (log(z^5)/log5)?
Originally Posted by stapel No. Are you saying that your 7s were actually the bases and the stuff you presented as exponents were really arguments? Yeah pretty much, sorry. I don't know exactly how to put logarithms into a computer.
change bases in logarithms so you can write to change it base so you can apply what I mention before consider as constant right
View Tag Cloud