Prove that equation , accepts an unique resolution : and :
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Originally Posted by dhiab Prove that equation , accepts an unique resolution : and : put , then: Now look at this has roots at and , so has constant sign for , a quick check shows that this is negative. Hence for Thus is decreasing when . To complete the proof it remains to show that is positive and is negative. CB
Hello captain thank you for your resolution Ajout : alpha = 1.91 and g(1.5)=0.5 , g(2)=-0.12
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