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Math Help - simplifying trignometric identity

  1. #1
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    simplifying trignometric identity

    how would you simplify 2sin3xcosx=1
    i've been stuck on this question for some time ;[
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  2. #2
    Master Of Puppets
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    consider  sin(a)cos(b) = \frac{1}{2}[sin(a+b)+sin(a-b)]<br />

    2sin(3x)cos(x)=1

    2(\frac{1}{2}[sin(3x+x)+sin(3x-x)])=1

    sin(3x+x)+sin(3x-x)=1

     <br />
sin(4x)+sin(2x)=1<br />
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