One end A of a light elastic string of natural length a and modulus of elasticity 6mg is fixed at a point on a smooth plane inclined at 30° to the horizontal A small ball B of mass m is attached to the other end of the string. Initially B is held at rest with the string lying along the line of greatest slope of the plane, with B below A and AB =a. The ball is released and comes to instantaneous rest at a point C on the plane.
Okay NOW It says I have to use a loss of GPE = EPE in the markscheme BUT WHY WHY WHY? Why cant I use
as the particle will stay be equilibrium when Tension balances the downward pull right?
right, but the position where the particle comes to rest is not the equilibrium position.
T = mgsin30°
therefore AC = a+a/12 = 13a/12
which is wrong!
Howcome????
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Originally Posted by thomas49th
One end A of a light elastic string of natural length a and modulus of elasticity 6mg is fixed at a point on a smooth plane inclined at 30° to the horizontal A small ball B of mass m is attached to the other end of the string. Initially B is held at rest with the string lying along the line of greatest slope of the plane, with B below A and AB =a. The ball is released and comes to instantaneous rest at a point C on the plane.
