
Originally Posted by
thomas49th
One end A of a light elastic string of natural length a and modulus of elasticity 6mg is fixed at a point on a smooth plane inclined at 30° to the horizontal A small ball B of mass m is attached to the other end of the string. Initially B is held at rest with the string lying along the line of greatest slope of the plane, with B below A and AB =a. The ball is released and comes to instantaneous rest at a point C on the plane.
Okay NOW It says I have to use a loss of GPE = EPE in the markscheme BUT WHY WHY WHY? Why cant I use
$\displaystyle Tension = \frac{\lambda x_{extension}}{x_{original length}}$
as the particle will stay be equilibrium when Tension balances the downward pull right? right, but the position where the particle comes to rest is not the equilibrium position.
T = mgsin30°
$\displaystyle Tension = \frac{\lambda x_{extension}}{x_{original length}} = mgsin30°$
$\displaystyle \frac{6mg x_{extension}}{a} = mgsin30°$
$\displaystyle \frac{6 x_{extension}}{a} = sin30°$
$\displaystyle x_{extension} = \frac{a}{12}$
therefore AC = a+a/12 = 13a/12
which is wrong!
Howcome????