I'm assuming that you mean this:

Now,

is the same as

, and

is the same as

:

Now, let's substitute 3^x = t as javax suggested:

Hey, that looks like a quadratic equation!

Solve for t:

or

But we're not done! We need to solve for

**x**. So substitute 3^x back in for t:

or

Hmm, there's

**no** x that would satisfy either equation. The base is positive and greater than 1, so the range of the function y = 3^x would be [0, ∞). So there is no solution, unless in the original equation the RHS equals some other number instead of 0.

01